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The value of 0.bar(2)+0.bar(3) +0.bar(4)...

The value of `0.bar(2)+0.bar(3) +0.bar(4)+0.bar(9) +0.bar(39)` is

A

`0.bar(57)`

B

`1 20/33`

C

`2 1/3`

D

`2 13/33 `

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem \(0.\overline{2} + 0.\overline{3} + 0.\overline{4} + 0.\overline{9} + 0.\overline{39}\), we need to convert each repeating decimal into a fraction. ### Step 1: Convert \(0.\overline{2}\) to a fraction The repeating decimal \(0.\overline{2}\) can be expressed as: \[ 0.\overline{2} = \frac{2}{9} \] ### Step 2: Convert \(0.\overline{3}\) to a fraction The repeating decimal \(0.\overline{3}\) can be expressed as: \[ 0.\overline{3} = \frac{3}{9} = \frac{1}{3} \] ### Step 3: Convert \(0.\overline{4}\) to a fraction The repeating decimal \(0.\overline{4}\) can be expressed as: \[ 0.\overline{4} = \frac{4}{9} \] ### Step 4: Convert \(0.\overline{9}\) to a fraction The repeating decimal \(0.\overline{9}\) can be expressed as: \[ 0.\overline{9} = \frac{9}{9} = 1 \] ### Step 5: Convert \(0.\overline{39}\) to a fraction The repeating decimal \(0.\overline{39}\) can be expressed as: \[ 0.\overline{39} = \frac{39}{99} = \frac{13}{33} \quad \text{(after simplifying)} \] ### Step 6: Sum all the fractions Now we can sum all the fractions we have found: \[ \frac{2}{9} + \frac{1}{3} + \frac{4}{9} + 1 + \frac{13}{33} \] To add these fractions, we need a common denominator. The least common multiple of \(9\), \(3\), and \(33\) is \(99\). ### Step 7: Convert each fraction to have a common denominator of \(99\) - Convert \(\frac{2}{9}\): \[ \frac{2}{9} = \frac{2 \times 11}{9 \times 11} = \frac{22}{99} \] - Convert \(\frac{1}{3}\): \[ \frac{1}{3} = \frac{1 \times 33}{3 \times 33} = \frac{33}{99} \] - Convert \(\frac{4}{9}\): \[ \frac{4}{9} = \frac{4 \times 11}{9 \times 11} = \frac{44}{99} \] - Convert \(1\): \[ 1 = \frac{99}{99} \] - Convert \(\frac{13}{33}\): \[ \frac{13}{33} = \frac{13 \times 3}{33 \times 3} = \frac{39}{99} \] ### Step 8: Add the fractions Now we can add all the fractions: \[ \frac{22}{99} + \frac{33}{99} + \frac{44}{99} + \frac{99}{99} + \frac{39}{99} = \frac{22 + 33 + 44 + 99 + 39}{99} = \frac{237}{99} \] ### Step 9: Simplify the fraction Now we simplify \(\frac{237}{99}\): \[ \frac{237 \div 9}{99 \div 9} = \frac{26.3333}{11} \quad \text{(not a whole number)} \] Since \(237\) and \(99\) share a common factor of \(9\): \[ \frac{237}{99} = \frac{79}{33} \] ### Final Answer Thus, the value of \(0.\overline{2} + 0.\overline{3} + 0.\overline{4} + 0.\overline{9} + 0.\overline{39}\) is: \[ \frac{79}{33} \]
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