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[3^(3)+3^(2)+3^(-2)+3^(-3)] is equal to...

`[3^(3)+3^(2)+3^(-2)+3^(-3)]` is equal to

A

0

B

`36+(1)/(36)`

C

`(976)/(27)`

D

`3^(5)+3^(-5)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( 3^{3} + 3^{2} + 3^{-2} + 3^{-3} \), we can break it down step by step. ### Step 1: Calculate each term First, we calculate the values of each term in the expression: 1. \( 3^{3} = 27 \) 2. \( 3^{2} = 9 \) 3. \( 3^{-2} = \frac{1}{3^{2}} = \frac{1}{9} \) 4. \( 3^{-3} = \frac{1}{3^{3}} = \frac{1}{27} \) ### Step 2: Write the expression with calculated values Now, we can rewrite the expression with the calculated values: \[ 27 + 9 + \frac{1}{9} + \frac{1}{27} \] ### Step 3: Combine the whole numbers Next, we combine the whole numbers: \[ 27 + 9 = 36 \] So, we have: \[ 36 + \frac{1}{9} + \frac{1}{27} \] ### Step 4: Find a common denominator for the fractions To add the fractions \( \frac{1}{9} \) and \( \frac{1}{27} \), we need a common denominator. The least common multiple (LCM) of 9 and 27 is 27. Now, we convert \( \frac{1}{9} \) to have a denominator of 27: \[ \frac{1}{9} = \frac{3}{27} \] ### Step 5: Add the fractions Now we can add the fractions: \[ \frac{3}{27} + \frac{1}{27} = \frac{3 + 1}{27} = \frac{4}{27} \] ### Step 6: Combine with the whole number Now, we combine this with the whole number: \[ 36 + \frac{4}{27} \] ### Step 7: Write the final answer To express this as a single fraction, we can convert 36 into a fraction with a denominator of 27: \[ 36 = \frac{36 \times 27}{27} = \frac{972}{27} \] Now, we add the two fractions: \[ \frac{972}{27} + \frac{4}{27} = \frac{972 + 4}{27} = \frac{976}{27} \] Thus, the final answer is: \[ \frac{976}{27} \]
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S CHAND IIT JEE FOUNDATION-POWERS AND ROOTS -SECTION-A (QUESTION BANK-5(A))
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  11. If (p/q)^(r x-s)=(q/p)^(p x-q) , then find the value of xdot

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