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If sqrt(x)+sqrt(441)=0. 02 , then the ...

If `sqrt(x)+sqrt(441)=0. 02` , then the value of `x` is (a) 0.1764 (b) 1.764 (c) 1.64 (d) 2.64

A

`1.64`

B

`2.64`

C

`1.764`

D

`0.1764`

Text Solution

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The correct Answer is:
D
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S CHAND IIT JEE FOUNDATION-POWERS AND ROOTS -SECTION-B SQUARE ROOTS AND CUBE ROOTS (QUESTION BANK 5(B))
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  12. Find the value of root3(sqrt(441)+sqrt(16)+sqrt(4))

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  13. Simplify sqrtroot3(0.000729)

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  14. Simplify (root3(8))/(sqrt(16))divsqrt(100)/(sqrt(49))xxroot3(125)

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