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Factorise the following : x^(2)+7x+10...

Factorise the following :
`x^(2)+7x+10`

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To factorise the expression \( x^2 + 7x + 10 \), we can follow these steps: ### Step 1: Identify the coefficients The given quadratic expression is in the form \( ax^2 + bx + c \), where: - \( a = 1 \) (coefficient of \( x^2 \)) - \( b = 7 \) (coefficient of \( x \)) - \( c = 10 \) (constant term) ### Step 2: Find two numbers that multiply to \( ac \) and add to \( b \) We need to find two numbers that: - Multiply to \( ac = 1 \times 10 = 10 \) - Add up to \( b = 7 \) The two numbers that satisfy these conditions are \( 5 \) and \( 2 \), since: - \( 5 \times 2 = 10 \) - \( 5 + 2 = 7 \) ### Step 3: Rewrite the middle term using the two numbers Now we can rewrite the expression by splitting the middle term \( 7x \) into \( 5x + 2x \): \[ x^2 + 5x + 2x + 10 \] ### Step 4: Group the terms Next, we group the terms: \[ (x^2 + 5x) + (2x + 10) \] ### Step 5: Factor out the common factors from each group From the first group \( (x^2 + 5x) \), we can factor out \( x \): \[ x(x + 5) \] From the second group \( (2x + 10) \), we can factor out \( 2 \): \[ 2(x + 5) \] ### Step 6: Combine the factored terms Now we can combine the factored terms: \[ x(x + 5) + 2(x + 5) \] We see that \( (x + 5) \) is a common factor: \[ (x + 5)(x + 2) \] ### Final Answer Thus, the factorised form of \( x^2 + 7x + 10 \) is: \[ (x + 5)(x + 2) \] ---
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