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Factorise the following : 5m^(2)-8m-4...

Factorise the following :
`5m^(2)-8m-4`

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To factorise the expression \(5m^2 - 8m - 4\), we will use the method of middle term splitting. Here’s a step-by-step solution: ### Step 1: Identify the coefficients The expression is in the form \(ax^2 + bx + c\), where: - \(a = 5\) - \(b = -8\) - \(c = -4\) ### Step 2: Multiply \(a\) and \(c\) Calculate the product of \(a\) and \(c\): \[ a \cdot c = 5 \cdot (-4) = -20 \] ### Step 3: Find two numbers that multiply to \(ac\) and add to \(b\) We need to find two numbers that multiply to \(-20\) and add to \(-8\). The numbers that satisfy this condition are \(-10\) and \(2\) because: \[ -10 \cdot 2 = -20 \quad \text{and} \quad -10 + 2 = -8 \] ### Step 4: Rewrite the middle term Now we can rewrite the expression by splitting the middle term: \[ 5m^2 - 10m + 2m - 4 \] ### Step 5: Group the terms Next, we will group the terms: \[ (5m^2 - 10m) + (2m - 4) \] ### Step 6: Factor out the common factors from each group From the first group \(5m^2 - 10m\), we can factor out \(5m\): \[ 5m(m - 2) \] From the second group \(2m - 4\), we can factor out \(2\): \[ 2(m - 2) \] ### Step 7: Combine the factored terms Now we can combine the factored terms: \[ 5m(m - 2) + 2(m - 2) \] Now, we can factor out the common term \((m - 2)\): \[ (m - 2)(5m + 2) \] ### Final Answer Thus, the factorised form of \(5m^2 - 8m - 4\) is: \[ (m - 2)(5m + 2) \] ---
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