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In an examination, A got 10% marks less ...

In an examination, A got 10% marks less than B. B got 25% marks more than C. C got 20% marks less than D. If A got 360 marks out of 500, the percentage of marks obtained by D was

A

70

B

75

C

80

D

85

Text Solution

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The correct Answer is:
To solve the problem step by step, we need to establish the relationships between the marks obtained by A, B, C, and D based on the information given. ### Step 1: Determine B's marks from A's marks We know that A got 10% marks less than B. If A got 360 marks, we can express this relationship mathematically. Let B's marks be represented as \( B \). According to the problem: \[ A = B - 0.10B \] \[ A = 0.90B \] Substituting A's marks: \[ 360 = 0.90B \] Now, we can solve for B: \[ B = \frac{360}{0.90} \] \[ B = 400 \] ### Step 2: Determine C's marks from B's marks Next, we know that B got 25% marks more than C. We can express this relationship as well. Let C's marks be represented as \( C \). According to the problem: \[ B = C + 0.25C \] \[ B = 1.25C \] Substituting B's marks: \[ 400 = 1.25C \] Now, we can solve for C: \[ C = \frac{400}{1.25} \] \[ C = 320 \] ### Step 3: Determine D's marks from C's marks Now we know that C got 20% marks less than D. We can express this relationship as follows. Let D's marks be represented as \( D \). According to the problem: \[ C = D - 0.20D \] \[ C = 0.80D \] Substituting C's marks: \[ 320 = 0.80D \] Now, we can solve for D: \[ D = \frac{320}{0.80} \] \[ D = 400 \] ### Step 4: Calculate the percentage of marks obtained by D Now that we have D's marks, we can calculate the percentage of marks obtained by D. The total marks are 500. Percentage of marks obtained by D: \[ \text{Percentage} = \left( \frac{D}{\text{Total Marks}} \right) \times 100 \] \[ \text{Percentage} = \left( \frac{400}{500} \right) \times 100 \] \[ \text{Percentage} = 80\% \] ### Final Answer The percentage of marks obtained by D is **80%**. ---
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