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A fan is listed at Rs. 1400 and the disc...

A fan is listed at Rs. 1400 and the discount offered is `10%` What additional discount must be given to bring the net selling price to Rs. 1200 ?

A

`16(2)/(3)%`

B

`5%`

C

`4(16)/(21)%`

D

`6%`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, let's break it down: ### Step 1: Calculate the initial selling price after the first discount. The listed price of the fan is Rs. 1400, and the discount offered is 10%. **Calculation:** - Discount = 10% of Rs. 1400 - Discount = (10/100) * 1400 = Rs. 140 Now, we subtract the discount from the listed price to find the selling price after the discount. - Selling Price after discount = Listed Price - Discount - Selling Price after discount = 1400 - 140 = Rs. 1260 ### Step 2: Determine the required selling price. We want the net selling price to be Rs. 1200. ### Step 3: Calculate the difference between the selling price after the first discount and the required selling price. **Calculation:** - Difference = Selling Price after discount - Required Selling Price - Difference = 1260 - 1200 = Rs. 60 ### Step 4: Calculate the additional discount percentage needed to achieve the required selling price. Let the additional discount be X%. We know that the additional discount of X% on the selling price after the first discount (which is Rs. 1260) should equal Rs. 60. **Calculation:** - Additional Discount = X% of Rs. 1260 - (X/100) * 1260 = 60 Now, we can solve for X: - X * 1260 = 60 * 100 - X * 1260 = 6000 - X = 6000 / 1260 - X = 4.76 (approximately) ### Step 5: Convert the decimal to a fraction. To express 4.76% as a fraction: - 4.76% = 4 + (76/100)% - 4.76% = 4 + (19/25)% - Convert to a common denominator if necessary. ### Conclusion: The additional discount required to bring the net selling price to Rs. 1200 is approximately 4.76%, which can be expressed as \(4 \frac{16}{21}\%\).
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S CHAND IIT JEE FOUNDATION-PROFIT AND LOSS AND DISCOUNT -SECTION - B (Question Bank - 11(b))
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