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A machine is sold at a profit of 10% Had...

A machine is sold at a profit of `10%` Had it been sold for Rs. 40 less, there would have been a loss of `10%`. What was the cost price ?

A

Rs. 175

B

Rs. 200

C

Rs. 225

D

Rs. 250

Text Solution

AI Generated Solution

The correct Answer is:
To find the cost price of the machine, we can follow these steps: ### Step 1: Define the Cost Price Let the cost price (CP) of the machine be Rs. X. ### Step 2: Calculate Selling Price at 10% Profit The selling price (SP) when sold at a profit of 10% can be calculated using the formula: \[ \text{SP} = \text{CP} + \text{Profit} \] Where Profit = 10% of CP = \( \frac{10}{100} \times X = \frac{X}{10} \) Thus, the selling price at 10% profit is: \[ \text{SP} = X + \frac{X}{10} = \frac{10X}{10} + \frac{X}{10} = \frac{11X}{10} \] ### Step 3: Calculate Selling Price at 10% Loss If the machine is sold for Rs. 40 less, the selling price becomes: \[ \text{SP} = \frac{11X}{10} - 40 \] When sold at a loss of 10%, the selling price can also be expressed as: \[ \text{SP} = \text{CP} - \text{Loss} \] Where Loss = 10% of CP = \( \frac{10}{100} \times X = \frac{X}{10} \) Thus, the selling price at 10% loss is: \[ \text{SP} = X - \frac{X}{10} = \frac{10X}{10} - \frac{X}{10} = \frac{9X}{10} \] ### Step 4: Set Up the Equation According to the problem, both expressions for selling price are equal: \[ \frac{11X}{10} - 40 = \frac{9X}{10} \] ### Step 5: Solve the Equation Now, we can solve for X: 1. Rearranging the equation gives: \[ \frac{11X}{10} - \frac{9X}{10} = 40 \] \[ \frac{2X}{10} = 40 \] \[ 2X = 400 \] \[ X = 200 \] ### Conclusion The cost price of the machine is Rs. 200. ---
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