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A can do a work in 18 days, B in 9 days ...

A can do a work in 18 days, B in 9 days and C in 6 days. A and B start working together and after 2 days C joins them. What is the total number of days taken to finish the work ?

A

`4.33`

B

`4.5`

C

`4.66`

D

None

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will determine how much work A, B, and C can do individually and then collectively to find out the total time taken to finish the work. ### Step 1: Determine the work done by A, B, and C in one day. - A can complete the work in 18 days. Therefore, the work done by A in one day is: \[ \text{Work done by A in one day} = \frac{1}{18} \] - B can complete the work in 9 days. Therefore, the work done by B in one day is: \[ \text{Work done by B in one day} = \frac{1}{9} \] - C can complete the work in 6 days. Therefore, the work done by C in one day is: \[ \text{Work done by C in one day} = \frac{1}{6} \] ### Step 2: Calculate the work done by A and B together in 2 days. - The combined work done by A and B in one day is: \[ \text{Work done by A and B in one day} = \frac{1}{18} + \frac{1}{9} \] To add these fractions, we need a common denominator. The least common multiple of 18 and 9 is 18. \[ \frac{1}{9} = \frac{2}{18} \] Thus, \[ \text{Work done by A and B in one day} = \frac{1}{18} + \frac{2}{18} = \frac{3}{18} = \frac{1}{6} \] - In 2 days, the work done by A and B is: \[ \text{Work done by A and B in 2 days} = 2 \times \frac{1}{6} = \frac{2}{6} = \frac{1}{3} \] ### Step 3: Calculate the remaining work after 2 days. - The total work is considered as 1 unit. After A and B have worked for 2 days, the remaining work is: \[ \text{Remaining work} = 1 - \frac{1}{3} = \frac{2}{3} \] ### Step 4: Calculate the work done by A, B, and C together in one day. - Now, we calculate the combined work done by A, B, and C in one day: \[ \text{Work done by A, B, and C in one day} = \frac{1}{18} + \frac{1}{9} + \frac{1}{6} \] Again, we need a common denominator. The least common multiple of 18, 9, and 6 is 18. \[ \frac{1}{9} = \frac{2}{18}, \quad \frac{1}{6} = \frac{3}{18} \] Thus, \[ \text{Work done by A, B, and C in one day} = \frac{1}{18} + \frac{2}{18} + \frac{3}{18} = \frac{6}{18} = \frac{1}{3} \] ### Step 5: Calculate the number of days required to finish the remaining work. - The remaining work is \(\frac{2}{3}\). The number of days required by A, B, and C to finish this remaining work is: \[ \text{Days required} = \frac{\text{Remaining work}}{\text{Work done by A, B, and C in one day}} = \frac{\frac{2}{3}}{\frac{1}{3}} = 2 \text{ days} \] ### Step 6: Calculate the total number of days taken to finish the work. - The total number of days taken to finish the work is: \[ \text{Total days} = \text{Days worked by A and B} + \text{Days worked by A, B, and C} = 2 + 2 = 4 \text{ days} \] ### Final Answer: The total number of days taken to finish the work is **4 days**. ---
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