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The sum of the squares of three numbers ...

The sum of the squares of three numbers which are in the ratio 2:3:4 is 725. What are these numbers?

A

10, 15, 20

B

14, 21, 28

C

20, 15, 30

D

20, 30, 40

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The correct Answer is:
To solve the problem step by step, we will follow the method outlined in the video transcript. ### Step 1: Define the Numbers Let the three numbers be represented in terms of a variable \( x \). Since the numbers are in the ratio 2:3:4, we can express them as: - First number = \( 2x \) - Second number = \( 3x \) - Third number = \( 4x \) ### Step 2: Set Up the Equation According to the problem, the sum of the squares of these numbers is equal to 725. Therefore, we can write the equation: \[ (2x)^2 + (3x)^2 + (4x)^2 = 725 \] ### Step 3: Expand the Squares Now, we will expand the squares in the equation: \[ 4x^2 + 9x^2 + 16x^2 = 725 \] ### Step 4: Combine Like Terms Next, we combine the like terms (the \( x^2 \) terms): \[ (4 + 9 + 16)x^2 = 725 \] This simplifies to: \[ 29x^2 = 725 \] ### Step 5: Solve for \( x^2 \) Now, we will isolate \( x^2 \) by dividing both sides of the equation by 29: \[ x^2 = \frac{725}{29} \] Calculating the right side gives: \[ x^2 = 25 \] ### Step 6: Solve for \( x \) Taking the square root of both sides, we find: \[ x = \sqrt{25} = 5 \] ### Step 7: Find the Numbers Now that we have the value of \( x \), we can find the actual numbers: - First number = \( 2x = 2 \times 5 = 10 \) - Second number = \( 3x = 3 \times 5 = 15 \) - Third number = \( 4x = 4 \times 5 = 20 \) ### Final Answer Thus, the three numbers are 10, 15, and 20. ---
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S CHAND IIT JEE FOUNDATION-RATIO AND PROPORTION -QUESTION BANK -15
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