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If the length and breadth of a rectangul...

If the length and breadth of a rectangular plot are each increased by 1 m, then the area of the floor is increased by 21 sq m. If the length is increased by 1 m and breadth is decreased by 1 m, then the area is decreased by 5 sq m. What is is the perimeter of the floor ?

A

30 m

B

32 m

C

36 m

D

40 m

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The correct Answer is:
To solve the problem step by step, we will denote the length of the rectangular plot as \( L \) meters and the breadth as \( B \) meters. ### Step 1: Set up the equations based on the problem statement. 1. **First Condition**: When both length and breadth are increased by 1 meter, the area increases by 21 square meters. - The original area \( A = L \times B \). - The new area after increasing both dimensions: \[ (L + 1)(B + 1) = LB + 21 \] - Expanding the left side: \[ LB + L + B + 1 = LB + 21 \] - Simplifying gives: \[ L + B + 1 = 21 \] - Thus, we can rearrange it to: \[ L + B = 20 \quad \text{(Equation 1)} \] 2. **Second Condition**: When the length is increased by 1 meter and the breadth is decreased by 1 meter, the area decreases by 5 square meters. - The new area in this case: \[ (L + 1)(B - 1) = LB - 5 \] - Expanding the left side: \[ LB - L + B - 1 = LB - 5 \] - Simplifying gives: \[ -L + B - 1 = -5 \] - Rearranging leads to: \[ -L + B = -4 \quad \text{or} \quad B - L = 4 \quad \text{(Equation 2)} \] ### Step 2: Solve the system of equations. We now have two equations: 1. \( L + B = 20 \) (Equation 1) 2. \( B - L = 4 \) (Equation 2) From Equation 2, we can express \( B \) in terms of \( L \): \[ B = L + 4 \] Substituting this expression for \( B \) into Equation 1: \[ L + (L + 4) = 20 \] \[ 2L + 4 = 20 \] Subtracting 4 from both sides: \[ 2L = 16 \] Dividing by 2: \[ L = 8 \] Now substituting \( L = 8 \) back into Equation 1 to find \( B \): \[ 8 + B = 20 \] \[ B = 20 - 8 = 12 \] ### Step 3: Calculate the perimeter. The perimeter \( P \) of a rectangle is given by the formula: \[ P = 2(L + B) \] Substituting the values of \( L \) and \( B \): \[ P = 2(8 + 12) = 2 \times 20 = 40 \text{ meters} \] ### Final Answer: The perimeter of the floor is **40 meters**. ---
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S CHAND IIT JEE FOUNDATION-PERIMETER AND AREA -QUESTION BANK - 21(A)
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