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If the longer side of a rectangle is dou...

If the longer side of a rectangle is doubled and the other is reduced to half, then the area of the new rectangle goes up by :

A

`50% `

B

`100% `

C

`0% `

D

`150%`

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The correct Answer is:
To solve the problem step by step, we will follow the given scenario of changing the dimensions of a rectangle and calculating the area increment. ### Step-by-Step Solution: 1. **Define the Dimensions of the Rectangle:** Let the longer side of the rectangle be \( L \) and the shorter side be \( B \). 2. **Calculate the Area of the Original Rectangle:** The area \( A \) of the original rectangle can be calculated using the formula: \[ A = L \times B \] 3. **Change the Dimensions:** According to the problem: - The longer side is doubled: New length = \( 2L \) - The shorter side is reduced to half: New breadth = \( \frac{B}{2} \) 4. **Calculate the Area of the New Rectangle:** The area \( A' \) of the new rectangle can be calculated as: \[ A' = (2L) \times \left(\frac{B}{2}\right) \] Simplifying this gives: \[ A' = 2L \times \frac{B}{2} = L \times B = A \] 5. **Calculate the Change in Area:** The change in area can be calculated as: \[ \text{Change in Area} = A' - A = A - A = 0 \] 6. **Calculate the Percentage Increase in Area:** To find the percentage increase in area, we use the formula: \[ \text{Percentage Increase} = \left(\frac{\text{Change in Area}}{\text{Original Area}}\right) \times 100 \] Substituting the values: \[ \text{Percentage Increase} = \left(\frac{0}{A}\right) \times 100 = 0\% \] ### Final Answer: The area of the new rectangle goes up by **0%**.
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S CHAND IIT JEE FOUNDATION-VOLUME AND SURFACE AREA OF A CUBE AND A CUBOID-UNIT TEST - 5
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