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If U = {3, 4, 5, 6, 7,8, 9} X = {3, 4}, ...

If U = {3, 4, 5, 6, 7,8, 9} X = {3, 4}, Y = {5, 6} and Z = {7, 8, 9} then `Y' cap (X cap Z)'` is equal to

A

`X cup Y`

B

`Y cup Z`

C

`(X cup Z)'`

D

`X' cap Y'`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find \( Y' \cap (X \cap Z)' \). ### Step 1: Identify the Universal Set and the Sets Given: - Universal Set \( U = \{3, 4, 5, 6, 7, 8, 9\} \) - Set \( X = \{3, 4\} \) - Set \( Y = \{5, 6\} \) - Set \( Z = \{7, 8, 9\} \) ### Step 2: Find the Complement of Set Y The complement of set \( Y \) (denoted as \( Y' \)) is found by subtracting the elements of \( Y \) from the universal set \( U \). \[ Y' = U - Y = \{3, 4, 5, 6, 7, 8, 9\} - \{5, 6\} = \{3, 4, 7, 8, 9\} \] ### Step 3: Find the Intersection of Sets X and Z Next, we need to find the intersection of sets \( X \) and \( Z \) (denoted as \( X \cap Z \)). \[ X \cap Z = \{3, 4\} \cap \{7, 8, 9\} = \emptyset \] ### Step 4: Find the Complement of the Intersection Now, we find the complement of the intersection \( (X \cap Z)' \). Since \( X \cap Z = \emptyset \), its complement is: \[ (X \cap Z)' = U - (X \cap Z) = U - \emptyset = U = \{3, 4, 5, 6, 7, 8, 9\} \] ### Step 5: Find the Intersection of Y' and (X ∩ Z)' Now we need to find the intersection of \( Y' \) and \( (X \cap Z)' \). \[ Y' \cap (X \cap Z)' = \{3, 4, 7, 8, 9\} \cap \{3, 4, 5, 6, 7, 8, 9\} \] The common elements are: \[ Y' \cap (X \cap Z)' = \{3, 4, 7, 8, 9\} \] ### Final Result Thus, the final result is: \[ Y' \cap (X \cap Z)' = \{3, 4, 7, 8, 9\} \]
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