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Evalaute 0.bar14+ 0. bar19...

Evalaute `0.bar14+ 0. bar19`

A

`(1)/(2)`

B

`(1)/(3)`

C

2

D

10

Text Solution

AI Generated Solution

The correct Answer is:
To evaluate \( 0.\overline{14} + 0.\overline{19} \), we will follow these steps: ### Step 1: Convert the repeating decimals to fractions The repeating decimal \( 0.\overline{14} \) can be expressed as a fraction using the formula: \[ 0.\overline{xy} = \frac{xy}{99} \] where \( xy \) is the repeating part. Here, \( xy = 14 \). So, we have: \[ 0.\overline{14} = \frac{14}{99} \] Similarly, for \( 0.\overline{19} \): \[ 0.\overline{19} = \frac{19}{99} \] ### Step 2: Add the fractions Now, we can add the two fractions: \[ 0.\overline{14} + 0.\overline{19} = \frac{14}{99} + \frac{19}{99} \] Since the denominators are the same, we can combine the numerators: \[ = \frac{14 + 19}{99} = \frac{33}{99} \] ### Step 3: Simplify the fraction Now, we simplify \( \frac{33}{99} \): \[ \frac{33}{99} = \frac{33 \div 33}{99 \div 33} = \frac{1}{3} \] ### Final Answer Thus, the value of \( 0.\overline{14} + 0.\overline{19} \) is: \[ \frac{1}{3} \] ---
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