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The rational expression (8x^3 - 125)/(4x...

The rational expression `(8x^3 - 125)/(4x^2 +10x+ 25)` in its simplest form is :

A

`2 x `

B

`5 `

C

`2x + 5 `

D

`2x - 5`

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The correct Answer is:
To simplify the rational expression \((8x^3 - 125)/(4x^2 + 10x + 25)\), we can follow these steps: ### Step 1: Factor the Numerator The numerator \(8x^3 - 125\) is a difference of cubes. We can use the identity for factoring a difference of cubes: \[ a^3 - b^3 = (a - b)(a^2 + ab + b^2) \] Here, \(a = 2x\) and \(b = 5\) (since \(8x^3 = (2x)^3\) and \(125 = 5^3\)). Using the identity: \[ 8x^3 - 125 = (2x - 5)((2x)^2 + (2x)(5) + 5^2) \] Calculating the terms: \[ (2x)^2 = 4x^2, \quad (2x)(5) = 10x, \quad 5^2 = 25 \] Thus, we have: \[ 8x^3 - 125 = (2x - 5)(4x^2 + 10x + 25) \] ### Step 2: Write the Rational Expression Now we can rewrite the rational expression: \[ \frac{8x^3 - 125}{4x^2 + 10x + 25} = \frac{(2x - 5)(4x^2 + 10x + 25)}{4x^2 + 10x + 25} \] ### Step 3: Simplify the Expression Since \(4x^2 + 10x + 25\) is present in both the numerator and the denominator, we can cancel it out (as long as \(4x^2 + 10x + 25 \neq 0\)): \[ = 2x - 5 \] ### Final Answer Thus, the simplest form of the given rational expression is: \[ \boxed{2x - 5} \] ---
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S CHAND IIT JEE FOUNDATION-HCF AND LCM OF POLYNOMIALS AND RATIONAL EXPRESSIONS-Question Bank
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  11. The HCF of two polynomials 4x^2(x^2 – 3x+2) and 12x(x-2)(x^2 - 4) is 4...

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  12. The rational expression (8x^3 - 125)/(4x^2 +10x+ 25) in its simplest f...

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  13. sqrt(((x^2 + 3x + 2)(x^2 + 5x + 6))/(x^2 (x^2 + 4x+ 3))) is equal to :

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  14. If A = (2x + 1)/(2x - 1) and B = (2x - 1)/(2x + 1) then A - B is equa...

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  15. 1/(x + 1) - 1/(x - 1) - (x^2)/(x + 1) + (x^2)/(x -1), when simplified ...

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  16. The product of the rational expressions (x^2 - y^2)/(x^2 + 2xy + y^2) ...

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  17. ((2x + y)/(x + y) - 1) div (1 - y/(x + y)) is equal to :

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  18. (x^3 + y^3 + z^3 - 3xyz)/(a^3 + b^3 + c^3 - 3abc) xx (a^2 + b^2 + c^2 ...

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  19. What should be added to a/(a - b) + b/(a + b) to get 1?

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  20. Simplify : [1/(1 + a) + (2a)/(1 - a^2)] xx ((a^2 + 4a - 5)/(a^2 + 10a ...

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