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The value of (x + y)/(x - y) + (x - y)/(...

The value of `(x + y)/(x - y) + (x - y)/(x + y) - (2(x^2 - y^2))/(x^2 - y^2)` is :

A

`1`

B

`x`

C

`y`

D

`0`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \(\frac{x + y}{x - y} + \frac{x - y}{x + y} - \frac{2(x^2 - y^2)}{x^2 - y^2}\), we will follow these steps: ### Step 1: Identify the common denominator The denominators in the first two fractions are \(x - y\) and \(x + y\). The least common denominator (LCD) for these fractions is \( (x^2 - y^2) \), since \( x^2 - y^2 = (x - y)(x + y) \). ### Step 2: Rewrite each term with the common denominator We can rewrite the expression as follows: \[ \frac{(x + y)^2}{(x - y)(x + y)} + \frac{(x - y)^2}{(x + y)(x - y)} - \frac{2(x^2 - y^2)}{x^2 - y^2} \] This simplifies to: \[ \frac{(x + y)^2 + (x - y)^2 - 2(x^2 - y^2)}{x^2 - y^2} \] ### Step 3: Expand the numerators Now we will expand the numerators: 1. \((x + y)^2 = x^2 + 2xy + y^2\) 2. \((x - y)^2 = x^2 - 2xy + y^2\) Putting these into the expression gives: \[ \frac{(x^2 + 2xy + y^2) + (x^2 - 2xy + y^2) - 2(x^2 - y^2)}{x^2 - y^2} \] ### Step 4: Combine like terms in the numerator Now we combine the terms in the numerator: \[ = \frac{(x^2 + 2xy + y^2 + x^2 - 2xy + y^2) - 2(x^2 - y^2)}{x^2 - y^2} \] Simplifying the numerator: \[ = \frac{2x^2 + 2y^2 - 2(x^2 - y^2)}{x^2 - y^2} \] ### Step 5: Simplify the numerator further Distributing the \(-2\) in the numerator: \[ = \frac{2x^2 + 2y^2 - 2x^2 + 2y^2}{x^2 - y^2} \] This simplifies to: \[ = \frac{4y^2}{x^2 - y^2} \] ### Step 6: Final expression Thus, the value of the original expression is: \[ \frac{4y^2}{x^2 - y^2} \]
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