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If 2/x+3/y=2 and 6/x+18/y=9, then the va...

If `2/x+3/y=2` and `6/x+18/y=9`, then the values of x and y respectively are:

A

3 and 2

B

2 and 3

C

4 and 3

D

3 and 4

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The correct Answer is:
To solve the equations \( \frac{2}{x} + \frac{3}{y} = 2 \) and \( \frac{6}{x} + \frac{18}{y} = 9 \), we will follow these steps: ### Step 1: Rewrite the equations Let \( m = \frac{1}{x} \) and \( n = \frac{1}{y} \). Then we can rewrite the equations as: 1. \( 2m + 3n = 2 \) (Equation 1) 2. \( 6m + 18n = 9 \) (Equation 2) ### Step 2: Simplify Equation 2 We can simplify Equation 2 by dividing all terms by 3: \[ 2m + 6n = 3 \] Now we have: 1. \( 2m + 3n = 2 \) (Equation 1) 2. \( 2m + 6n = 3 \) (Equation 2) ### Step 3: Solve for one variable Now, we can subtract Equation 1 from Equation 2: \[ (2m + 6n) - (2m + 3n) = 3 - 2 \] This simplifies to: \[ 3n = 1 \] Thus, we find: \[ n = \frac{1}{3} \] ### Step 4: Substitute n back to find m Now substitute \( n \) back into Equation 1 to find \( m \): \[ 2m + 3\left(\frac{1}{3}\right) = 2 \] This simplifies to: \[ 2m + 1 = 2 \] Subtracting 1 from both sides gives: \[ 2m = 1 \] Thus, we find: \[ m = \frac{1}{2} \] ### Step 5: Find x and y Recall that \( m = \frac{1}{x} \) and \( n = \frac{1}{y} \). Therefore: \[ x = \frac{1}{m} = \frac{1}{\frac{1}{2}} = 2 \] \[ y = \frac{1}{n} = \frac{1}{\frac{1}{3}} = 3 \] ### Final Answer Thus, the values of \( x \) and \( y \) are: \[ x = 2, \quad y = 3 \]
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