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One of the factors of a^(6)+b^(6)-a^(2)b...

One of the factors of `a^(6)+b^(6)-a^(2)b^(4)-a^(4)b^(2)` is

A

`a+1`

B

`a^(2)+b^(2)`

C

`a^(3)+b^(3)`

D

`a^(4)+b^(4)`

Text Solution

AI Generated Solution

The correct Answer is:
To find one of the factors of the expression \( a^6 + b^6 - a^2b^4 - a^4b^2 \), we can follow these steps: ### Step 1: Rewrite the expression The given expression is: \[ a^6 + b^6 - a^2b^4 - a^4b^2 \] ### Step 2: Group the terms We can group the terms in pairs: \[ (a^6 - a^4b^2) + (b^6 - a^2b^4) \] ### Step 3: Factor out common terms From the first group \( a^6 - a^4b^2 \), we can factor out \( a^4 \): \[ a^4(a^2 - b^2) \] From the second group \( b^6 - a^2b^4 \), we can factor out \( b^4 \): \[ b^4(b^2 - a^2) \] So, we have: \[ a^4(a^2 - b^2) + b^4(b^2 - a^2) \] ### Step 4: Notice the common factor Now, we can see that \( b^2 - a^2 = -(a^2 - b^2) \). Thus, we can write: \[ a^4(a^2 - b^2) - b^4(a^2 - b^2) \] ### Step 5: Factor out \( (a^2 - b^2) \) Now we can factor out \( (a^2 - b^2) \): \[ (a^2 - b^2)(a^4 - b^4) \] ### Step 6: Factor \( a^4 - b^4 \) The expression \( a^4 - b^4 \) can be factored further using the difference of squares: \[ a^4 - b^4 = (a^2 + b^2)(a^2 - b^2) \] ### Step 7: Combine the factors Now we can combine all the factors: \[ (a^2 - b^2)(a^2 + b^2)(a^2 - b^2) \] This simplifies to: \[ (a^2 - b^2)^2(a^2 + b^2) \] ### Final Result Thus, one of the factors of the expression \( a^6 + b^6 - a^2b^4 - a^4b^2 \) is: \[ a^2 - b^2 \] ---
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S CHAND IIT JEE FOUNDATION-MATRICES -UNIT TEST -2
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