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The LCM of the polynomials (x^(8)-y^(8))...

The LCM of the polynomials `(x^(8)-y^(8))` and `(x^(4)-y^(4))(x+y)` is

A

`(x^(8)-y^(8))`

B

`(x^(8)-y^(8))(x^(4)-y^(4))(x+y)`

C

`(x^(8)-y^(8))(x+y)`

D

`(x^(4)-y^(4))(x^(8)-y^(8))`

Text Solution

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The correct Answer is:
To find the LCM of the polynomials \(x^8 - y^8\) and \((x^4 - y^4)(x + y)\), we can follow these steps: ### Step 1: Factor the first polynomial \(x^8 - y^8\) We can use the difference of squares identity: \[ x^8 - y^8 = (x^4)^2 - (y^4)^2 = (x^4 - y^4)(x^4 + y^4) \] ### Step 2: Write the second polynomial The second polynomial is already given as: \[ (x^4 - y^4)(x + y) \] ### Step 3: Identify the common factors Now we have: 1. From the first polynomial: \( (x^4 - y^4)(x^4 + y^4) \) 2. From the second polynomial: \( (x^4 - y^4)(x + y) \) The common factor between both polynomials is \(x^4 - y^4\). ### Step 4: Determine the LCM The LCM is obtained by taking the highest power of each factor present in both polynomials. Thus, we have: \[ \text{LCM} = (x^4 - y^4)(x^4 + y^4)(x + y) \] ### Final Answer The LCM of the polynomials \(x^8 - y^8\) and \((x^4 - y^4)(x + y)\) is: \[ (x^4 - y^4)(x^4 + y^4)(x + y) \] ---
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S CHAND IIT JEE FOUNDATION-MATRICES -UNIT TEST -2
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  6. The factors of (a^(2)+36b^(2))^(2)-169a^(2)b^(2) are:

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  7. One of the factors of a^(6)+b^(6)-a^(2)b^(4)-a^(4)b^(2) is

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  20. The LCM of the polynomials (x^(8)-y^(8)) and (x^(4)-y^(4))(x+y) is

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