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A sold a watch to B at 20% gain and B so...

A sold a watch to B at 20% gain and B sold it to C at a loss of 10%. If C bought the watch for Rs 216, at what price did A purchase it?

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To find out at what price A purchased the watch, we can break down the problem step by step. ### Step 1: Define the Cost Price of A Let the cost price of the watch for A be Rs. X. ### Step 2: Calculate Selling Price of A A sold the watch to B at a gain of 20%. Therefore, the selling price (SP) for A can be calculated as: \[ SP_A = X + 20\% \text{ of } X = X + \frac{20}{100} \times X = X + \frac{1}{5}X = \frac{6X}{5} \] ### Step 3: Calculate Cost Price of B Now, B sold the watch to C at a loss of 10%. The selling price for B can be calculated as: \[ SP_B = \frac{6X}{5} - 10\% \text{ of } \frac{6X}{5} = \frac{6X}{5} - \frac{10}{100} \times \frac{6X}{5} = \frac{6X}{5} - \frac{1}{10} \times \frac{6X}{5} \] Calculating \(10\% \text{ of } \frac{6X}{5}\): \[ = \frac{6X}{5} - \frac{6X}{50} = \frac{6X}{5} - \frac{3X}{25} \] To subtract these fractions, we need a common denominator: \[ = \frac{30X}{25} - \frac{3X}{25} = \frac{27X}{25} \] ### Step 4: Set Selling Price of C We know that C bought the watch for Rs. 216. Therefore, we can set up the equation: \[ \frac{27X}{25} = 216 \] ### Step 5: Solve for X To find X, we multiply both sides by 25: \[ 27X = 216 \times 25 \] Calculating \(216 \times 25\): \[ 216 \times 25 = 5400 \] Now, divide both sides by 27: \[ X = \frac{5400}{27} \] Calculating \(5400 \div 27\): \[ X = 200 \] ### Conclusion Thus, the cost price at which A purchased the watch is Rs. 200. ---
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