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A shopkeeper sells 100 kg of sugar partl...

A shopkeeper sells 100 kg of sugar partly at 10% profit and the remaining at 20% profit. If he gains 12% on the whole transaction, how much sugar did he sell at 20% profit?

A

25 kg

B

40 kg

C

20 kg

D

30 kg

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we can follow these steps: ### Step 1: Define Variables Let: - \( x \) = the amount of sugar sold at 20% profit (in kg) - \( 100 - x \) = the amount of sugar sold at 10% profit (in kg) ### Step 2: Set Up the Cost Price Assume the cost price of sugar per kg is \( Y \). Therefore, the total cost price of 100 kg of sugar is: \[ \text{Total Cost Price} = 100Y \] ### Step 3: Calculate Selling Prices - Selling price for \( x \) kg of sugar sold at 20% profit: \[ \text{Selling Price at 20%} = x \times Y \times (1 + 0.20) = x \times Y \times 1.20 = 1.2xY \] - Selling price for \( 100 - x \) kg of sugar sold at 10% profit: \[ \text{Selling Price at 10%} = (100 - x) \times Y \times (1 + 0.10) = (100 - x) \times Y \times 1.10 = 1.1(100 - x)Y \] ### Step 4: Total Selling Price The total selling price (SP) of the sugar is the sum of the selling prices: \[ \text{Total Selling Price} = 1.2xY + 1.1(100 - x)Y \] ### Step 5: Gain on the Whole Transaction The shopkeeper gains 12% on the whole transaction, so: \[ \text{Total Selling Price} = \text{Total Cost Price} + 12\% \text{ of Total Cost Price} \] \[ \text{Total Selling Price} = 100Y + 0.12 \times 100Y = 100Y \times 1.12 = 112Y \] ### Step 6: Set Up the Equation Now, we can set the total selling price equal to the expression we derived: \[ 1.2xY + 1.1(100 - x)Y = 112Y \] ### Step 7: Simplify the Equation Dividing the entire equation by \( Y \) (assuming \( Y \neq 0 \)): \[ 1.2x + 1.1(100 - x) = 112 \] Expanding this gives: \[ 1.2x + 110 - 1.1x = 112 \] ### Step 8: Combine Like Terms Combine the \( x \) terms: \[ (1.2 - 1.1)x + 110 = 112 \] \[ 0.1x + 110 = 112 \] ### Step 9: Solve for \( x \) Subtract 110 from both sides: \[ 0.1x = 2 \] Now divide by 0.1: \[ x = \frac{2}{0.1} = 20 \] ### Conclusion The amount of sugar sold at 20% profit is \( \boxed{20 \text{ kg}} \). ---
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