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A diagonal of a rectangle is inclined to...

A diagonal of a rectangle is inclined to one side of a rectangle at `34^(@)`. The acute angle between the diagonals is :

A

`34^(@)`

B

`56^(@)`

C

`68^(@)`

D

`42^(@)`

Text Solution

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The correct Answer is:
To find the acute angle between the diagonals of a rectangle when one diagonal is inclined to one side of the rectangle at \(34^\circ\), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Rectangle and Diagonals**: - Let the rectangle be \(ABCD\) with vertices \(A\), \(B\), \(C\), and \(D\). - The diagonals \(AC\) and \(BD\) intersect at point \(O\). 2. **Identifying the Given Angle**: - The diagonal \(AC\) is inclined to side \(AD\) at an angle of \(34^\circ\). - This means that \(\angle ODC = 34^\circ\). 3. **Finding Angle ADO**: - Since the angles in a rectangle are \(90^\circ\), we can find \(\angle ADO\) using: \[ \angle ADO = 90^\circ - \angle ODC \] - Substituting the value: \[ \angle ADO = 90^\circ - 34^\circ = 56^\circ \] 4. **Using Properties of Diagonals**: - The diagonals of a rectangle bisect each other and are equal in length. - Therefore, \(\angle OAD\) will also be equal to \(\angle ADO\): \[ \angle OAD = 56^\circ \] 5. **Finding the Angle AOD**: - Now, we know that the sum of angles in triangle \(AOD\) is \(180^\circ\): \[ \angle AOD + \angle OAD + \angle ADO = 180^\circ \] - Substituting the known values: \[ \angle AOD + 56^\circ + 56^\circ = 180^\circ \] - Simplifying: \[ \angle AOD + 112^\circ = 180^\circ \] - Therefore: \[ \angle AOD = 180^\circ - 112^\circ = 68^\circ \] 6. **Identifying the Acute Angle**: - The acute angle between the diagonals \(AC\) and \(BD\) is \(\angle AOD\), which we calculated to be \(68^\circ\). ### Final Answer: The acute angle between the diagonals of the rectangle is \(68^\circ\). ---
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