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A cube having each side of unit length i...

A cube having each side of unit length is cut into two parts by plane through two diagonals of two opposite faces. What is the total surface area of each of these parts ?

A

`3+sqrt(2)` sq. units

B

`2+sqrt(3)` sq. units

C

`3sqrt(2)` sq. units

D

3 sq. units

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The correct Answer is:
To find the total surface area of each part of the cube after it has been cut by a plane through two diagonals of two opposite faces, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Cube's Dimensions**: - The cube has a side length of 1 unit. Therefore, the dimensions of the cube are 1 unit x 1 unit x 1 unit. 2. **Calculate the Total Surface Area of the Cube**: - The formula for the total surface area (SA) of a cube is given by: \[ SA = 6 \times (\text{side length})^2 \] - Substituting the side length: \[ SA = 6 \times (1)^2 = 6 \text{ square units} \] 3. **Identify the Plane Cutting the Cube**: - The cube is cut by a plane through the diagonals of two opposite faces. This means we need to understand how this cut affects the surface area. 4. **Determine the New Surface Areas Created by the Cut**: - The cut creates two new triangular faces. Each triangular face is formed by the diagonals of the square faces of the cube. - The area of one triangular face can be calculated using the formula for the area of a triangle: \[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \] - The base and height of the triangle formed by the diagonal of a square face (1 unit x 1 unit) are both equal to 1 unit. Therefore, the area of one triangular face is: \[ \text{Area} = \frac{1}{2} \times 1 \times 1 = \frac{1}{2} \text{ square units} \] - Since there are two triangular faces created by the cut, the total area contributed by these triangular faces is: \[ 2 \times \frac{1}{2} = 1 \text{ square unit} \] 5. **Calculate the Total Surface Area of Each Part**: - Each part of the cube will have half of the original surface area plus the area of the new triangular faces. Therefore, the total surface area of one part is: \[ \text{Total Surface Area of One Part} = \frac{6}{2} + 1 = 3 + 1 = 4 \text{ square units} \] ### Final Answer: The total surface area of each part after the cube is cut is **4 square units**.
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S CHAND IIT JEE FOUNDATION-VOLUME AND SURFACE AREA -Section A (Question Bank - 27)
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  2. The volume of a rectangular block of stone is 10368 dm3. Its dimens...

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  3. One cubic metre of copper is melted and recast into a square cross - s...

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  4. A water tank is 30 m long, 20 m wide and 12 m deep. It is made of i...

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  5. The sum of the length, breadth and depth of a cuboid is 19cm and it...

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  6. A solid cube with an edge 10 cm is melted to form two equal cubes. The...

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  7. A rectangular tank 25 cm long and 20 cm wide contains 4.5 litres of wa...

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  8. An icecream company makes a popular brand of icecream in a rectangular...

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  9. Three cubes with sides in the ratio 3 : 4 : 5 are melted to form a ...

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  10. A, B, C denote the areas of three co-terminus faces of a cuboid. If P ...

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  11. A cuboid has edges of x cm, 1 cm and 2 cm. The total surface area of t...

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  12. A metallic sheet is of the rectangular shape with dimensions 48 c m...

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  13. Except for one face of a given cube, identical cubes are glued thro...

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  14. A cube having each side of unit length is cut into two parts by plane ...

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  15. A cuboid is formed of 3 edges measuring 3,4 and 5 cm. It is sliced int...

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  16. A square hole of cross - sectional area 4" cm"^(2) is drilled across a...

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  17. The area of a side of a box is 120 sq. cm. The area of the other side ...

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  18. A rectangular tank is 225 m by 162 m at the base. With what speed must...

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  19. Water in a rectangular reservoir having base 80m by 60m is 6.5m dee...

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  20. A cake as shown has three layers , each of which is a cuboid as shown....

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