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The difference between the outside and inside surfaces of a cylindrical metal pipe 14 cm long is `44" cm"^(2)`. It the pipe is made of `99" cm"^(3)` of metal, find the sum of the inner and outer radii of the pipe ?

A

`4.5` cm

B

`3.5` cm

C

2 cm

D

`5.5` cm

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the information given about the cylindrical metal pipe. ### Step 1: Understand the Given Information - Length of the pipe (height, H) = 14 cm - Difference between the outside and inside surface area = 44 cm² - Volume of the metal used = 99 cm³ Let: - Inner radius = R1 - Outer radius = R2 ### Step 2: Write the Formula for Curved Surface Area The curved surface area (CSA) of a cylinder is given by the formula: \[ \text{CSA} = 2\pi r h \] For the inner and outer surfaces, we have: - Inner CSA = \( 2\pi R1 H \) - Outer CSA = \( 2\pi R2 H \) ### Step 3: Set Up the Equation for Surface Area Difference According to the problem, the difference between the outer and inner surface areas is: \[ 2\pi R2 H - 2\pi R1 H = 44 \] Factoring out \( 2\pi H \): \[ 2\pi H (R2 - R1) = 44 \] ### Step 4: Substitute Known Values Substituting H = 14 cm: \[ 2\pi (14) (R2 - R1) = 44 \] \[ 28\pi (R2 - R1) = 44 \] Dividing both sides by \( 28\pi \): \[ R2 - R1 = \frac{44}{28\pi} \] Using \( \pi \approx \frac{22}{7} \): \[ R2 - R1 = \frac{44}{28 \times \frac{22}{7}} = \frac{44 \times 7}{28 \times 22} = \frac{308}{616} = \frac{1}{2} \text{ cm} \] ### Step 5: Write the Volume Equation The volume of the pipe can be expressed as the difference between the volume of the outer cylinder and the inner cylinder: \[ V = \pi R2^2 H - \pi R1^2 H \] Factoring out \( \pi H \): \[ V = \pi H (R2^2 - R1^2) \] Substituting V = 99 cm³ and H = 14 cm: \[ 99 = \pi (14) (R2^2 - R1^2) \] ### Step 6: Substitute the Value of π Using \( \pi \approx \frac{22}{7} \): \[ 99 = \frac{22}{7} (14) (R2^2 - R1^2) \] \[ 99 = \frac{308}{7} (R2^2 - R1^2) \] Multiplying both sides by 7: \[ 693 = 308 (R2^2 - R1^2) \] Dividing both sides by 308: \[ R2^2 - R1^2 = \frac{693}{308} = \frac{99}{44} = \frac{9}{4} \] ### Step 7: Use the Difference of Squares Using the identity \( a^2 - b^2 = (a - b)(a + b) \): \[ R2^2 - R1^2 = (R2 - R1)(R2 + R1) \] Substituting \( R2 - R1 = \frac{1}{2} \): \[ \frac{9}{4} = \frac{1}{2} (R2 + R1) \] Multiplying both sides by 2: \[ \frac{9}{2} = R2 + R1 \] ### Step 8: Conclusion Thus, the sum of the inner and outer radii of the pipe is: \[ R1 + R2 = 4.5 \text{ cm} \]
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