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A 10 m long flagstaff is fixed on the to...

A 10 m long flagstaff is fixed on the top of a tower from a point on the ground, the angles of elevations of the top and bottom of flagstaff are `45^(@) and 30^(@)` respectively. Find the height of the tower

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To solve the problem, we need to find the height of the tower given the angles of elevation to the top and bottom of a flagstaff. Here’s a step-by-step solution: ### Step 1: Understand the Geometry We have a tower (BC) and a flagstaff (AB) on top of it. The height of the flagstaff (AB) is given as 10 m. The angles of elevation from a point on the ground to the bottom (A) and top (B) of the flagstaff are 30° and 45°, respectively. ### Step 2: Set Up the Problem Let: - \( h \) = height of the tower (BC) - The total height from the ground to the top of the flagstaff (B) = \( h + 10 \) m ### Step 3: Use the Angle of Elevation to Set Up Equations 1. From the point on the ground to the top of the flagstaff (B), the angle of elevation is 45°: \[ \tan(45°) = \frac{h + 10}{x} \] Since \( \tan(45°) = 1 \): \[ 1 = \frac{h + 10}{x} \implies x = h + 10 \quad \text{(Equation 1)} \] 2. From the point on the ground to the bottom of the flagstaff (A), the angle of elevation is 30°: \[ \tan(30°) = \frac{h}{x} \] Since \( \tan(30°) = \frac{1}{\sqrt{3}} \): \[ \frac{1}{\sqrt{3}} = \frac{h}{x} \implies x = \sqrt{3}h \quad \text{(Equation 2)} \] ### Step 4: Substitute Equation 2 into Equation 1 From Equation 1, we have: \[ x = h + 10 \] From Equation 2, we have: \[ x = \sqrt{3}h \] Setting these two expressions for \( x \) equal to each other: \[ h + 10 = \sqrt{3}h \] ### Step 5: Solve for \( h \) Rearranging the equation: \[ \sqrt{3}h - h = 10 \] Factoring out \( h \): \[ h(\sqrt{3} - 1) = 10 \] Now, solve for \( h \): \[ h = \frac{10}{\sqrt{3} - 1} \] ### Step 6: Rationalize the Denominator To simplify \( h \): \[ h = \frac{10(\sqrt{3} + 1)}{(\sqrt{3} - 1)(\sqrt{3} + 1)} = \frac{10(\sqrt{3} + 1)}{3 - 1} = \frac{10(\sqrt{3} + 1)}{2} \] \[ h = 5(\sqrt{3} + 1) \] ### Step 7: Calculate the Numerical Value Using \( \sqrt{3} \approx 1.732 \): \[ h \approx 5(1.732 + 1) = 5(2.732) \approx 13.66 \text{ m} \] ### Conclusion The height of the tower is approximately \( 13.66 \) meters. ---
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S CHAND IIT JEE FOUNDATION-SOME APPLICATIONS OF TRIGONOMETRY-Unit Test - 6
  1. A 10 m long flagstaff is fixed on the top of a tower from a point on t...

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  2. If tan x = (3)/( 4) , 0 lt x lt 90^(@) , then what is value of sin x ...

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  3. What is the expression (tan x )/( 1 + sec x) - (tan x)/( 1 - sec x) e...

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  4. If tan theta = 1 and sin phi = (1)/(sqrt(2)), and theta, phi in[0,pi/...

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  5. If cos theta = (3)/(5) , then the value of (sin theta - tan theta + ...

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  6. Given x cos theta + y sin theta = 2 and x cos theta - y sin theta ...

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  7. Which of the following is /are the value (s) of the the expression ? ...

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  8. If sin A = (2 m n)/( m^(2) + n^(2)) , What is the value of tan A ?

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  9. If sec^(2) theta + tan^(2) theta = (5)/(3) and 0 le theta le (pi)/(2)...

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  10. Evaluate : (5 sin ^(2) 30^(@) + cos ^(2) 45^(@) + 4 tan ^(2) 60^(@))/(...

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  11. Evaluate : ( 5 cos ^(2) 60^(@) + 4 sec^(2) 30^(@) - tan^(2) 45^(@))/( ...

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  12. The value of sin^(2) 1^(@) + sin^(2) 2^(@) + sin^(2) 3^(@)+ . . . . +...

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  13. If tan 2 A = cot ( A - 60^(@)) , where 2 A is an acute angle then th...

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  14. Evaluate : ( 2 cos 53^(@) cosec 37^(@))/(( cos^(2) 29^(@) + cos^(2) 61...

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  15. Evaluate : sin theta cos theta - (sin theta cos (90^(@) - theta) co...

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  16. Using trigonometric identities 5 cosec ^(2) theta - 5 cot ^(2) theta ...

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  17. The angle of elevation of the top of a tower at a horizontal distanc...

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  18. a person aims at a bird on top of a 5 metre high pole with an elevati...

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  19. Horizontal distance between two pillars of different heights is 60 m...

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  20. The angles of elevation of the top of a tower h metre tall from two di...

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  21. A radio transmitter antenna of height 100 m stands at the top of a ta...

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