If the force remains constant and the area is doubled, then the pressure will be

Options

A. half
B. three times
C. two times
D. none of these

Answer

To solve the problem, we need to understand the relationship between force, area, and pressure. The formula for pressure (P) is given by:

\[ P = \frac{F}{A} \]

Where:
- \( P \) is the pressure,
- \( F \) is the force applied,
- \( A \) is the area over which the force is applied.

### Step-by-Step Solution:

1. **Identify the Initial Conditions:**
- Let the initial force be \( F \).
- Let the initial area be \( A \).

2. **Calculate Initial Pressure:**
- Using the formula for pressure, the initial pressure \( P_1 \) can be calculated as:
\[ P_1 = \frac{F}{A} \]

3. **Identify the New Conditions:**
- According to the problem, the area is doubled. Therefore, the new area \( A_2 \) is:
\[ A_2 = 2A \]

4. **Calculate Final Pressure:**
- The final pressure \( P_2 \) can be calculated using the new area while keeping the force constant:
\[ P_2 = \frac{F}{A_2} = \frac{F}{2A} \]

5. **Simplify the Final Pressure:**
- We can rewrite the final pressure as:
\[ P_2 = \frac{F}{2A} = \frac{1}{2} \cdot \frac{F}{A} = \frac{1}{2} P_1 \]

6. **Conclusion:**
- Since \( P_1 = \frac{F}{A} \), we find that:
\[ P_2 = \frac{1}{2} P_1 \]
- This means that if the area is doubled while keeping the force constant, the pressure is halved.

### Final Answer:
The pressure will be half of the initial pressure.