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A freely suspended magnet always lies in...

A freely suspended magnet always lies in

A

North-South direction

B

North-East direction

C

East-West direction

D

South-Bast direction

Text Solution

AI Generated Solution

To solve the question "A freely suspended magnet always lies in," we need to understand the behavior of magnets when they are allowed to move freely. ### Step-by-Step Solution: 1. **Understanding Magnet Behavior**: A magnet has two poles: a north pole and a south pole. When a magnet is freely suspended, it can rotate and align itself according to the Earth's magnetic field. 2. **Suspension of the Magnet**: When we suspend a magnet using a thread or rope, it is free to rotate. The north pole of the magnet will experience a force that aligns it with the Earth's magnetic field. ...
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Explain, why a freely suspended magnet always points in the north-south direction.

(a) Define magnetic field lines. Describe an activity to draw a magnetic field line outside a bar magnet from one pole to another pole. (b) Explain why, a freely suspended magnet always points in the north-south direction.

Knowledge Check

  • A freely suspended magnet comes to rest in the.

    A
    north-south direction.
    B
    north-east direction.
    C
    north-west direction.
    D
    east-west direction.

  • A freely suspended magnet comes to rest in the ____ direction.

    A
    North-South
    B
    North-East
    C
    South-West
    D
    North-West

  • The time period of oscillations of a freely suspended magnetic needle is given by

    A
    `T= 2pi sqrt((I)/(mB_H))`
    B
    `T= 2pi sqrt((mB_H)/(I))`
    C
    `T= sqrt((I)/(mB_H))`
    D
    `T= 2pi sqrt((B_H)/(mI))`

    • Similar Questions

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    A freely suspended magnet lies in the horizontal plane at ___________of earth.

    Statement-1 A freely suspended bar magnet always comes to lie in North-South direction. Statement-2 Magnetic poles have the property of directionality

    A freely suspended bar magnet makes an angle of 60^@ with the horizontal component and 45^@ with the magnetic meridian of a place. Calculate the angle of dip for that place.

    Which pole of a freely suspended magnet will move along magnetic field lines?

    At a place, a freely suspended magnet shows a dip angle of 30^(@) . If the plane of the magnet is at an angle of 45^(@) from the magnetic meridian, then the real dip of the magnet will be

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