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An effort of 10 kgf is applied on a mach...

An effort of 10 kgf is applied on a machine through a displacement of 105 cm, when a load of 200 kgf moves through a distance of 5 cm. Calculate mechanical advantage.

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Given load L = mg = `6 xx 10` = 60 N and effort E=70 N
Now mechanical advantage
`=("load")/("effort") =(60N)/(70N)=0.86`37.) Mechanical advantage= `("load")/("effort") =(200)/(10)= 20`
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