The mechanical advantage of a machine is 5 and its efficiency is 75%. A load of 300 kgf is lifted with the help of this machine up to the height of 15 m. Calculate the work done by the machine. (g = 10 `m s^(-2)`)

Explanation

To solve the problem, we need to calculate the work done by the machine based on the given mechanical advantage, efficiency, load, and height. Here’s a step-by-step breakdown of the solution:

### Step 1: Convert Load from kgf to Newtons
The load is given as 300 kgf. To convert this to Newtons, we use the formula:
\[ \text{Load (N)} = \text{Load (kgf)} \times g \]
Where \( g = 10 \, \text{m/s}^2 \).

Calculating:
...