2000 J of energy is needed to heat 1 kg of paraffin through `2^(@)C`, then its specific heat capacity is

Options

A. `4000 J//kg^(@)C`
B. `10, 000J//kg^(@)C`
C. `40, 000J//kg^(@)C`
D. `1000J//kg^(@)C`

Explanation

To find the specific heat capacity of paraffin, we can use the formula:

\[ Q = mc\Delta T \]

Where:
- \( Q \) is the heat energy supplied (in joules),
- \( m \) is the mass of the substance (in kilograms),
- \( c \) is the specific heat capacity (in joules per kg per degree Celsius),
- \( \Delta T \) is the change in temperature (in degrees Celsius).

### Step-by-Step Solution:

1. **Identify the given values**:
- Heat energy (\( Q \)) = 2000 J
- Mass (\( m \)) = 1 kg
- Change in temperature (\( \Delta T \)) = 2 °C

2. **Substitute the values into the formula**:
We need to rearrange the formula to solve for specific heat capacity (\( c \)):
\[ c = \frac{Q}{m \Delta T} \]

3. **Plug in the known values**:
\[ c = \frac{2000 \, \text{J}}{1 \, \text{kg} \times 2 \, \text{°C}} \]

4. **Calculate the specific heat capacity**:
\[ c = \frac{2000 \, \text{J}}{2 \, \text{kg °C}} = 1000 \, \text{J/kg °C} \]

5. **Conclusion**:
The specific heat capacity of paraffin is \( 1000 \, \text{J/kg °C} \).

### Final Answer:
The specific heat capacity of paraffin is \( 1000 \, \text{J/kg °C} \).

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