Two blocks of metal, one twice as heavy as the other, are both at `60^(@)C`. The ratio of the heat energy of the heavier block to that of the lighter block is

Options

A. 0.5
B. 1
C. 2
D. 4

Explanation

To solve the problem of finding the ratio of the heat energy of the heavier block to that of the lighter block, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Masses of the Blocks:**
- Let the mass of the lighter block be \( m \).
- Since the heavier block is twice as heavy, its mass will be \( 2m \).

2. **Understand the Concept of Heat Energy:**
- The heat energy (\( Q \)) contained in a body can be calculated using the formula:
\[ Q = m \cdot S \cdot \Delta T \]
where:
- \( m \) = mass of the block
- \( S \) = specific heat capacity of the material
- \( \Delta T \) = change in temperature

3. **Assume Specific Heat Capacities:**
- Assume both blocks are made of the same material, so they have the same specific heat capacity \( S \).
- Since both blocks are at the same temperature of \( 60^\circ C \), we can assume \( \Delta T = 0 \) for this specific calculation, but we will focus on the ratio of heat energy based on their masses.

4. **Calculate Heat Energy for Each Block:**
- For the lighter block:
\[ Q_1 = m \cdot S \cdot \Delta T \]
- For the heavier block:
\[ Q_2 = 2m \cdot S \cdot \Delta T \]

5. **Find the Ratio of Heat Energies:**
- The ratio of the heat energy of the heavier block to that of the lighter block is:
\[ \text{Ratio} = \frac{Q_2}{Q_1} = \frac{2m \cdot S \cdot \Delta T}{m \cdot S \cdot \Delta T} \]
- Simplifying this gives:
\[ \text{Ratio} = \frac{2m}{m} = 2 \]

6. **Final Result:**
- Therefore, the ratio of the heat energy of the heavier block to that of the lighter block is \( 2:1 \).