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In a laboratory experiment to measure th...

In a laboratory experiment to measure the specific heat capacity of copper, 0.02 kg of water at `70^(@)C` was poured into a copper calorimeter with a stirrer of mass 0.16 kg initially at `15^(@)C`. After stirring the final temperature reached to `45^(@)C`.
What is the quantity of heat released per kg of water per `1^(@)C` fall in temperature ?

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To solve the problem, we need to calculate the quantity of heat released per kg of water per 1°C fall in temperature. This is essentially the specific heat capacity of water, which we know is approximately 4200 Joules/kg/°C. However, we will derive this value from the given data to ensure understanding. ### Step-by-Step Solution: 1. **Identify the Given Data:** - Mass of water, \( m_w = 0.02 \, \text{kg} \) - Initial temperature of water, \( T_{w_i} = 70 \, °C \) - Final temperature after mixing, \( T_f = 45 \, °C \) ...
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In a laboratory experiment to measure the specific heat capacity of copper, 0.02 kg of water at 70^(@)C was poured into a copper calorimeter with a stirrer of mass 0.16 kg initially at 15^(@)C . After stirring the final temperature reached to 45^(@)C . Assuming that heat released by water is entirely used to raise the temperature of calorimeter 15^(@)C to 45^(@)C , calculate the specific heat capacity of copper. (Specific heat capacity of water = 4200 J kg^(-1)""^(@)C^(-1) .

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