Home
Class 8
PHYSICS
Suppose 2.5 kg of water is heated from 1...

Suppose 2.5 kg of water is heated from `10^(@)C` to `90^(@)C`. How much thermal energy would be transferred to the water? Water's sp. heat is `4,184 J//kg^(@)C`.

Text Solution

AI Generated Solution

To solve the problem of how much thermal energy is transferred to the water when it is heated from \(10^\circ C\) to \(90^\circ C\), we can use the formula for heat transfer: \[ Q = m \cdot C \cdot \Delta T \] Where: - \(Q\) = thermal energy (in Joules) ...
Promotional Banner

Similar Questions

Explore conceptually related problems

When water is heated from 0^(@)C to 10^(@)C , the volume of water

If 1000kg of water is heated from 0^(@)C to 100^(@)C , calculate the increase in mass of water.

400 kg of water is heated from 30^(@) C to 100^(@)C . What will be the increase in mass of water ? Take specific heat of wateer = 4.2 xx10^(3) " J kg"^(-1).^(@)C^(-1) .

If 2000kg of water is heated from 0^(@) C to 100^(@)C , what will be the corresponding increase in mass of water? Take specific heat of water =1cal. g^(-1).^(@)C^(-1) .

500 kg of water is heated from 20^(@) to 100^(@) C . Calculate the increase in the mass of water.Given specific heat of water =4.2 xx 10^(3) J kg ^(-1) .^(@)C^(-1) .

100g of water is heated from 30^@C to 50^@C . Ignoring the slight expansion of the water, the change in its internal energy is (specific heat of water is 4184J//kg//K ):

1 kg of water is heated from 40^(@) C "to" 70^(@)C ,If its volume remains constatn, then the change in internal energy is (specific heat of water = 4148 J kg^(-1 K^(-1))

Calculate the entropy change when 1 kg of water is heated from 27^(@)C to 200^(@)C forming supper heated steam under constant pressure. Given specific heat of water = 4180 J Kg^(-1)K^(-1) and specific heat of steam = 1670 + 0.49 J kg^(-1)K^(-1) and latent heat of vaporisation =23 xx 10^(5) J kg^(-1) .