The equation of line parallel to y = 0 and passing through the point (2, -5) is

Options

A. x=2
B. y=-5
C. y=2
D. x=-5

Answer

To find the equation of a line that is parallel to \( y = 0 \) (the x-axis) and passes through the point \( (2, -5) \), follow these steps:

### Step-by-Step Solution:

1. **Understand the given line**: The equation \( y = 0 \) represents the x-axis. A line parallel to this will also be horizontal, meaning it will have a constant y-value.

**Hint**: Remember that parallel lines have the same slope. The slope of the line \( y = 0 \) is 0.

2. **Identify the y-coordinate of the given point**: The point through which the new line passes is \( (2, -5) \). The y-coordinate here is \(-5\).

**Hint**: The y-coordinate of the point is the value that the new line will maintain since it is horizontal.

3. **Write the equation of the line**: Since the line is horizontal and passes through \( (2, -5) \), the equation of the line will be \( y = -5 \).

**Hint**: A horizontal line can be expressed as \( y = k \), where \( k \) is the y-value at which the line is located.

4. **Final equation**: Therefore, the equation of the line parallel to \( y = 0 \) and passing through the point \( (2, -5) \) is:

\[ y = -5 \]

### Summary:
The equation of the line is \( y = -5 \).