Find the sum.
`MCD + "CCL" + DCL`

Answer

To find the sum of MCD + CCL + DCL, we first need to convert each Roman numeral into its corresponding integer value.

### Step 1: Convert MCD to an integer
- M = 1000
- C = 100
- D = 500

In the Roman numeral MCD:
- M (1000) + C (100) + D (500) = 1000 + 100 + 500 = 1600
- However, since C is before D, it is subtracted: 500 - 100 = 400.
- Therefore, MCD = 1000 + 400 = 1400.

### Step 2: Convert CCL to an integer
- C = 100
- L = 50

In the Roman numeral CCL:
- C (100) + C (100) + L (50) = 100 + 100 + 50 = 250.
- Therefore, CCL = 250.

### Step 3: Convert DCL to an integer
- D = 500
- C = 100
- L = 50

In the Roman numeral DCL:
- D (500) + C (100) + L (50) = 500 + 100 + 50 = 650.
- Therefore, DCL = 650.

### Step 4: Add the integer values together
Now we will add the values we have calculated:
- MCD = 1400
- CCL = 250
- DCL = 650

So, the sum is:
1400 + 250 + 650 = 2300.

### Step 5: Convert the sum back to Roman numerals
To convert 2300 into Roman numerals:
- 2000 = MM (1000 + 1000)
- 300 = CCC (100 + 100 + 100)

Thus, 2300 in Roman numerals is MMCCC.

### Final Answer
The sum of MCD + CCL + DCL is **MMCCC**.

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