Find the product by suitable rearrangement.
`125xx43xx160`

Answer

To find the product of \( 125 \times 43 \times 160 \) using suitable rearrangement, we can follow these steps:

### Step 1: Rearrange the Numbers
We can rearrange the numbers to make the multiplication easier. Let's rearrange it as:
\[ 125 \times 160 \times 43 \]

### Step 2: Multiply \( 125 \) and \( 160 \)
Now, we will first multiply \( 125 \) by \( 160 \). We can simplify this multiplication:
\[ 125 \times 160 = 125 \times (16 \times 10) = (125 \times 16) \times 10 \]

### Step 3: Calculate \( 125 \times 16 \)
To calculate \( 125 \times 16 \):
- \( 125 \times 16 = 2000 \)

So, we have:
\[ 125 \times 160 = 2000 \times 10 = 20000 \]

### Step 4: Multiply the Result by \( 43 \)
Now, we will multiply \( 20000 \) by \( 43 \):
\[ 20000 \times 43 = 20000 \times (40 + 3) = (20000 \times 40) + (20000 \times 3) \]

### Step 5: Calculate Each Part
- First, calculate \( 20000 \times 40 \):
\[ 20000 \times 40 = 800000 \]

- Next, calculate \( 20000 \times 3 \):
\[ 20000 \times 3 = 60000 \]

### Step 6: Add the Two Results
Now, we add the two results together:
\[ 800000 + 60000 = 860000 \]

### Final Answer
Thus, the final product of \( 125 \times 43 \times 160 \) is:
\[ \boxed{860000} \]

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