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Find the product by suitable rearrangeme...

Find the product by suitable rearrangement:
`8xx291xx125`

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The correct Answer is:
To find the product of \( 8 \times 291 \times 125 \) using suitable rearrangement, we can follow these steps: ### Step 1: Rearrange the numbers We can rearrange the numbers as \( 8 \times 125 \times 291 \). ### Step 2: Express the numbers in exponential form We can express \( 8 \) and \( 125 \) in terms of their prime factors: - \( 8 = 2^3 \) - \( 125 = 5^3 \) ### Step 3: Combine the factors Now we can rewrite the expression: \[ 8 \times 125 = 2^3 \times 5^3 \] This can be combined as: \[ (2 \times 5)^3 = 10^3 \] ### Step 4: Multiply by 291 Now we have: \[ 10^3 \times 291 \] Calculating \( 10^3 \): \[ 10^3 = 1000 \] So we need to calculate: \[ 1000 \times 291 \] ### Step 5: Perform the multiplication To multiply \( 1000 \times 291 \): \[ 1000 \times 291 = 291000 \] ### Final Answer Thus, the product \( 8 \times 291 \times 125 = 291000 \). ---
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