Where will the hand of a clock stop if it
starts at 2 and makes `(1)/(2)` of a revolution, clockwise ?

Answer

To solve the problem of where the hand of a clock will stop if it starts at 2 and makes \( \frac{1}{2} \) of a revolution clockwise, we can follow these steps:

### Step 1: Understand the Clock Positions
A clock has 12 positions, numbered from 1 to 12. The positions are:
- 12 at the top
- 3 on the right
- 6 at the bottom
- 9 on the left

### Step 2: Identify the Starting Position
The hand of the clock starts at the number 2.

### Step 3: Determine the Amount of Revolution
A full revolution (360 degrees) means the hand goes all the way around the clock and returns to the same position. Half of a revolution is \( \frac{1}{2} \) of 360 degrees, which is 180 degrees.

### Step 4: Calculate the New Position
When the hand moves 180 degrees clockwise from 2:
- From 2, moving clockwise:
- 3 (90 degrees)
- 4 (180 degrees)

Thus, after moving 180 degrees clockwise from 2, the hand will stop at 8.

### Step 5: Conclusion
The hand of the clock will stop at 8 after making \( \frac{1}{2} \) of a revolution clockwise starting from 2.

### Final Answer
The hand of the clock stops at 8.

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