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If a shape is completely bounded by plan...

If a shape is completely bounded by plane faces, what is the least number of faces it may have ?

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To determine the least number of faces a shape can have if it is completely bounded by plane faces, we can analyze the properties of polyhedra. ### Step-by-Step Solution: 1. **Understanding Solid Shapes**: A solid shape is defined as a three-dimensional figure that is completely enclosed by flat surfaces (faces). Each face is a polygon. 2. **Identifying Simple Shapes**: The simplest three-dimensional shape is a tetrahedron, which is also known as a triangular pyramid. 3. **Counting Faces of a Tetrahedron**: A tetrahedron has: - 4 triangular faces (each face is a triangle). - 4 vertices (corners of the shape). - 6 edges (the line segments where two faces meet). 4. **Conclusion**: Since the tetrahedron is the simplest polyhedron and has 4 faces, we conclude that the least number of faces a shape can have, while being completely bounded by plane faces, is **4**. ### Final Answer: The least number of faces a shape may have is **4**.
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