Draw any angle with vertex O Take a point A on one of its arms and B on another such that OA = OB. Draw the perpendicular bisectors of `bar(OA)` and `bar(OB).` Let them meet at P. Is PA = PB ?

Draw a line segment PQ of length 10 cm. Take a point R on it at a distance 4 cm from P. Draw a line perpendicular to bar (PQ) through R. Also find bar(PQ).

Draw a circle with centre O and radius 3.2 cm. Take a points A and B on the circle Such that angleAOB=60^(@). Let the bisector of angleAOB intersect the circle in point K. Draw a circle passing through K such that ray OA and ray OB are tangents to it.

Draw any line segment bar(PQ). Take any point R not on it. Through R, draw a perpendicular to bar(PQ) (use ruler and set-square)

On the circle with centre O, points A, B are such that OA =AB. A point C is located on the tangent at B to the circle such that A and C are on the opposite sides of the line OB and Ab =BC. The line segment AC intersects the circle again at F. Then the ratio angleBOF: angle BOC is equal to-

Let O be any point in the interior of DeltaABC , prove that : AB+BC+CA lt 2 (OA+OB+OC)

Draw the perpendicular bisector of bar(XY) whose length is 10.3 cm. Take any point P on the bisector drawn. Examine whether PX = PY.

Let O , A , B be three collinear points such that OA.OB=1 . If O and B represent the complex numbers O and z , then A represents

O is the origin in the Cartesian plane. From the origin O take point A in the North-East direction such that |OA| =5, B is a point in the North-West direction such that |OB| = 5.Then |OA-OB| is (A) 25 (B) 5sqrt2 (C) 10sqrt5 (D) sqrt5