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Find the product of (3)/(7) and reciproc...

Find the product of `(3)/(7)` and reciprocal of `(2)/(7) + (1)/(14).`

A

`6/5`

B

`(15)/(98)`

C

`(-6)/(5)`

D

`(5)/(14)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the product of \(\frac{3}{7}\) and the reciprocal of \(\frac{2}{7} + \frac{1}{14}\). Let's break it down step by step. ### Step 1: Find the sum of \(\frac{2}{7}\) and \(\frac{1}{14}\) To add these two fractions, we need to have a common denominator. The least common multiple (LCM) of 7 and 14 is 14. - Convert \(\frac{2}{7}\) to a fraction with a denominator of 14: \[ \frac{2}{7} = \frac{2 \times 2}{7 \times 2} = \frac{4}{14} \] Now we can add: \[ \frac{4}{14} + \frac{1}{14} = \frac{4 + 1}{14} = \frac{5}{14} \] ### Step 2: Find the reciprocal of \(\frac{5}{14}\) The reciprocal of a fraction is obtained by flipping the numerator and the denominator. Therefore: \[ \text{Reciprocal of } \frac{5}{14} = \frac{14}{5} \] ### Step 3: Find the product of \(\frac{3}{7}\) and \(\frac{14}{5}\) Now we multiply \(\frac{3}{7}\) by \(\frac{14}{5}\): \[ \frac{3}{7} \times \frac{14}{5} = \frac{3 \times 14}{7 \times 5} = \frac{42}{35} \] ### Step 4: Simplify \(\frac{42}{35}\) To simplify \(\frac{42}{35}\), we can divide both the numerator and the denominator by their greatest common divisor (GCD), which is 7: \[ \frac{42 \div 7}{35 \div 7} = \frac{6}{5} \] ### Step 5: Convert \(\frac{6}{5}\) to a mixed number \(\frac{6}{5}\) can also be expressed as a mixed number: \[ 6 \div 5 = 1 \quad \text{(remainder 1)} \] So, \(\frac{6}{5} = 1 \frac{1}{5}\). ### Final Answer The product of \(\frac{3}{7}\) and the reciprocal of \(\frac{2}{7} + \frac{1}{14}\) is: \[ \frac{6}{5} \text{ or } 1 \frac{1}{5} \] ---
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