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The product of three rational numbes is ...

The product of three rational numbes is `( - (4)/(11))` If two of the numbers are `(- (2)/(3)) and (- (1)/(11)),` then find the third number.

A

`-6`

B

6

C

11

D

`-11`

Text Solution

AI Generated Solution

The correct Answer is:
To find the third rational number when the product of three rational numbers is given, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Information:** We know that the product of three rational numbers \( x, y, z \) is given as: \[ x \cdot y \cdot z = -\frac{4}{11} \] Two of the numbers are: \[ x = -\frac{2}{3}, \quad y = -\frac{1}{11} \] We need to find \( z \). 2. **Substitute the Known Values:** Substitute the values of \( x \) and \( y \) into the equation: \[ -\frac{2}{3} \cdot -\frac{1}{11} \cdot z = -\frac{4}{11} \] 3. **Calculate the Product of \( x \) and \( y \):** First, calculate the product of \( x \) and \( y \): \[ -\frac{2}{3} \cdot -\frac{1}{11} = \frac{2}{3 \cdot 11} = \frac{2}{33} \] 4. **Set Up the Equation:** Now, substitute this product back into the equation: \[ \frac{2}{33} \cdot z = -\frac{4}{11} \] 5. **Isolate \( z \):** To find \( z \), multiply both sides of the equation by the reciprocal of \( \frac{2}{33} \): \[ z = -\frac{4}{11} \cdot \frac{33}{2} \] 6. **Simplify the Right Side:** Now, perform the multiplication: \[ z = -\frac{4 \cdot 33}{11 \cdot 2} \] Simplifying this gives: \[ z = -\frac{132}{22} = -6 \] 7. **Conclusion:** Therefore, the third rational number \( z \) is: \[ z = -6 \]
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