Find the value of the expressions, when `p= -3, q= -1" and "r= 2`
`4pq^(2)+7qr-6pr`

Answer

To find the value of the expression \( 4pq^2 + 7qr - 6pr \) when \( p = -3 \), \( q = -1 \), and \( r = 2 \), we will substitute the values of \( p \), \( q \), and \( r \) into the expression step by step.

### Step 1: Substitute the values into the expression
We start with the expression:
\[ 4pq^2 + 7qr - 6pr \]
Substituting \( p = -3 \), \( q = -1 \), and \( r = 2 \):
\[ 4(-3)(-1)^2 + 7(-1)(2) - 6(-3)(2) \]

### Step 2: Calculate \( q^2 \)
Calculate \( (-1)^2 \):
\[ (-1)^2 = 1 \]
Now substitute this back into the expression:
\[ 4(-3)(1) + 7(-1)(2) - 6(-3)(2) \]

### Step 3: Calculate each term
Now we will calculate each term one by one.

1. **First term**: \( 4(-3)(1) \)
\[ = 4 \times -3 \times 1 = -12 \]

2. **Second term**: \( 7(-1)(2) \)
\[ = 7 \times -1 \times 2 = -14 \]

3. **Third term**: \( -6(-3)(2) \)
\[ = -6 \times -3 \times 2 = 36 \]

### Step 4: Combine the results
Now we combine all the calculated terms:
\[ -12 - 14 + 36 \]

### Step 5: Perform the addition and subtraction
Calculating step by step:
1. Combine the first two terms:
\[ -12 - 14 = -26 \]
2. Now add the third term:
\[ -26 + 36 = 10 \]

### Final Result
The value of the expression \( 4pq^2 + 7qr - 6pr \) when \( p = -3 \), \( q = -1 \), and \( r = 2 \) is:
\[ \boxed{10} \]