Simplify the expression and find its value when a = 3 and b = 1.
`2(a^(2) + ab) + 3 - ab`

Answer

To simplify the expression \(2(a^2 + ab) + 3 - ab\) and find its value when \(a = 3\) and \(b = 1\), we can follow these steps:

### Step 1: Substitute the values of \(a\) and \(b\)
We start by substituting \(a = 3\) and \(b = 1\) into the expression.

\[ 2((3)^2 + (3)(1)) + 3 - (3)(1) \]

### Step 2: Calculate \(a^2\) and \(ab\)
Next, we calculate \(3^2\) and \(3 \times 1\).

\[ 3^2 = 9 \]
\[ 3 \times 1 = 3 \]

### Step 3: Substitute the calculated values back into the expression
Now we can substitute these values back into the expression:

\[ 2(9 + 3) + 3 - 3 \]

### Step 4: Simplify inside the parentheses
Now we simplify inside the parentheses:

\[ 9 + 3 = 12 \]

### Step 5: Multiply by 2
Next, we multiply by 2:

\[ 2 \times 12 = 24 \]

### Step 6: Add and subtract the remaining terms
Now we add and subtract the remaining terms:

\[ 24 + 3 - 3 \]

### Step 7: Simplify the expression
Now we simplify:

\[ 24 + 3 = 27 \]
\[ 27 - 3 = 24 \]

### Final Answer
Thus, the value of the expression when \(a = 3\) and \(b = 1\) is:

\[ \boxed{24} \]

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