Tanmay had Rs. 56. He spent Rs x on transport and Rs 2 y on lunch. He spent the remaining amount to buy 3 similar books. What was the cost of the each book?

Options

A. Rs (56 - x + 2y)
B. Rs (56 - x - 2y)
C. `Rs ( 56 - x + 2y)/(3)`
D. ` Rs ( 56 - x - 2y )/(3)`

Answer

To solve the problem step by step, we can follow these instructions:

### Step 1: Understand the total amount Tanmay had
Tanmay had a total of Rs. 56.

### Step 2: Identify the expenses
- He spent Rs. \( x \) on transport.
- He spent Rs. \( 2y \) on lunch.

### Step 3: Calculate the remaining amount after expenses
The remaining amount after spending on transport and lunch can be calculated as:
\[ \text{Remaining Amount} = 56 - x - 2y \]

### Step 4: Determine the cost of the books
Tanmay used the remaining amount to buy 3 similar books. Let the cost of each book be \( z \). Therefore, the total cost for 3 books can be expressed as:
\[ \text{Total Cost for 3 Books} = 3z \]

### Step 5: Set up the equation
Since the remaining amount is equal to the total cost of the books, we can set up the equation:
\[ 56 - x - 2y = 3z \]

### Step 6: Solve for the cost of one book
To find the cost of one book \( z \), we can rearrange the equation:
\[ 3z = 56 - x - 2y \]
Now, divide both sides by 3:
\[ z = \frac{56 - x - 2y}{3} \]

### Final Answer
The cost of each book is:
\[ z = \frac{56 - x - 2y}{3} \]

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