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The H.C.F. of 14x^(3)y^(2) " and " 21y^(...

The H.C.F. of `14x^(3)y^(2) " and " 21y^(3)z^(2)` is

A

7xyz

B

`7x^(2)y`

C

`7y^(2)`

D

xyz

Text Solution

AI Generated Solution

The correct Answer is:
To find the H.C.F. (Highest Common Factor) of the algebraic expressions \(14x^3y^2\) and \(21y^3z^2\), we will follow these steps: ### Step 1: Factor the coefficients First, we need to factor the numerical coefficients of both expressions. - For \(14\): \[ 14 = 2 \times 7 \] - For \(21\): \[ 21 = 3 \times 7 \] ### Step 2: Identify the common factors of the coefficients Now, we look for the common factors in the coefficients \(14\) and \(21\). - The common factor is \(7\). ### Step 3: Factor the variables Next, we will factor the variable parts of both expressions. - The first expression \(14x^3y^2\) has: - \(x^3\) (which means \(x\) appears 3 times) - \(y^2\) (which means \(y\) appears 2 times) - The second expression \(21y^3z^2\) has: - \(y^3\) (which means \(y\) appears 3 times) - \(z^2\) (which means \(z\) appears 2 times) ### Step 4: Identify the common variables Now, we identify the common variables and their lowest powers. - The common variable is \(y\). - The lowest power of \(y\) in both expressions is \(y^2\). ### Step 5: Combine the common factors Now, we combine the common numerical factor and the common variable factor to find the H.C.F. \[ \text{H.C.F.} = 7y^2 \] ### Final Answer Thus, the H.C.F. of \(14x^3y^2\) and \(21y^3z^2\) is: \[ \boxed{7y^2} \]
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