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Find 'a' such that ((6)/(7))^(a)xx((6)/(...

Find 'a' such that `((6)/(7))^(a)xx((6)/(7))^(3a)=(1296)/(2401)`.

A

`4`

B

`1`

C

`0`

D

`5`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \(\left(\frac{6}{7}\right)^{a} \times \left(\frac{6}{7}\right)^{3a} = \frac{1296}{2401}\), we can follow these steps: ### Step 1: Combine the exponents on the left side Using the property of exponents that states \(a^m \times a^n = a^{m+n}\), we can combine the left side: \[ \left(\frac{6}{7}\right)^{a + 3a} = \left(\frac{6}{7}\right)^{4a} \] ### Step 2: Rewrite the right side Next, we need to express the right side \(\frac{1296}{2401}\) in terms of powers of \(\frac{6}{7}\). First, we can factor \(1296\) and \(2401\): - \(1296 = 6^4\) (since \(6 \times 6 \times 6 \times 6 = 1296\)) - \(2401 = 7^4\) (since \(7 \times 7 \times 7 \times 7 = 2401\)) Thus, we can rewrite the right side: \[ \frac{1296}{2401} = \frac{6^4}{7^4} = \left(\frac{6}{7}\right)^4 \] ### Step 3: Set the exponents equal Now we have: \[ \left(\frac{6}{7}\right)^{4a} = \left(\frac{6}{7}\right)^{4} \] Since the bases are the same, we can set the exponents equal to each other: \[ 4a = 4 \] ### Step 4: Solve for \(a\) Now, we can solve for \(a\): \[ a = \frac{4}{4} = 1 \] ### Final Answer Thus, the value of \(a\) is: \[ \boxed{1} \]
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MTG IIT JEE FOUNDATION-EXPONENTS AND POWERS-EXERCISE (MULTIPLE CHOICE QUESTION) (LEVEL -I)
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  11. Usual form of -4.8xx10^8 is

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  12. Simplify : 7^(16)xx7^(5)xx((1)/(7))^(11)

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  13. If [5^(9)xx5^(3)]div[5^(15)div5^(3)]=5^m, then find the value of m.

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  14. If (x)/(y)=((2)/(3))^(3)div((3)/(2))^2, then the value of ((x)/(y))^3 ...

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  15. Find the value of [{((-3)/(8))^2}^0]^(7).

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  16. Find the value of (3^(0)xx4^(0)+2^(0)xx3^0)/(16^0).

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  17. Find 'a' such that ((6)/(7))^(a)xx((6)/(7))^(3a)=(1296)/(2401).

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  18. Find the value of t, if (9^(0)xx5^(0)xx7^0)/((-1)^(23)xx(-1)^5)=7^t.

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  19. If x=((2)/(3))^(4)div((2)/(3))^2, find the value of x^5.

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  20. What is the value of x, if 64xx(512)^(2)=x^8?

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