The sum of four consecutive natural numbers is 722. Find the numbers.

Answer

To solve the problem of finding four consecutive natural numbers whose sum is 722, we can follow these steps:

### Step 1: Define the consecutive natural numbers
Let the first natural number be \( x \). Since we are looking for four consecutive natural numbers, we can express them as:
- First number: \( x \)
- Second number: \( x + 1 \)
- Third number: \( x + 2 \)
- Fourth number: \( x + 3 \)

### Step 2: Set up the equation
The sum of these four consecutive numbers can be expressed as:
\[ x + (x + 1) + (x + 2) + (x + 3) \]
This simplifies to:
\[ 4x + 6 \]

### Step 3: Set the equation equal to 722
According to the problem, the sum of these four numbers is 722. Therefore, we can set up the equation:
\[ 4x + 6 = 722 \]

### Step 4: Solve for \( x \)
To find \( x \), we first subtract 6 from both sides of the equation:
\[ 4x = 722 - 6 \]
\[ 4x = 716 \]
Now, divide both sides by 4:
\[ x = \frac{716}{4} \]
\[ x = 179 \]

### Step 5: Find the four consecutive numbers
Now that we have \( x \), we can find the four consecutive natural numbers:
- First number: \( 179 \)
- Second number: \( 180 \)
- Third number: \( 181 \)
- Fourth number: \( 182 \)

### Final Answer
The four consecutive natural numbers are **179, 180, 181, and 182**.

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