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If the diameter of base of a right circu...

If the diameter of base of a right circular cylinder is decreased by 10%, then volume of cylinder remains the same. Find the percentage increase in height.

A

0.2

B

0.2345

C

0.15

D

0.2054

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the percentage increase in height of a right circular cylinder when its diameter is decreased by 10% while keeping the volume constant. ### Step-by-Step Solution: 1. **Define the Initial Diameter and Radius:** - Let the initial diameter of the cylinder be \( D_1 = 100 \) cm. - The initial radius \( R_1 \) is half of the diameter: \[ R_1 = \frac{D_1}{2} = \frac{100}{2} = 50 \text{ cm} \] 2. **Calculate the Decreased Diameter and New Radius:** - The diameter is decreased by 10%, so the new diameter \( D_2 \) is: \[ D_2 = D_1 - 0.1 \times D_1 = 100 - 10 = 90 \text{ cm} \] - The new radius \( R_2 \) is: \[ R_2 = \frac{D_2}{2} = \frac{90}{2} = 45 \text{ cm} \] 3. **Set Up the Volume Equation:** - The volume \( V \) of a cylinder is given by the formula: \[ V = \pi R^2 H \] - For the initial cylinder: \[ V_1 = \pi R_1^2 H_1 = \pi (50)^2 H_1 = 2500\pi H_1 \] - For the new cylinder: \[ V_2 = \pi R_2^2 H_2 = \pi (45)^2 H_2 = 2025\pi H_2 \] - Since the volumes are equal (\( V_1 = V_2 \)): \[ 2500\pi H_1 = 2025\pi H_2 \] 4. **Cancel \(\pi\) and Rearrange:** - Cancel \(\pi\) from both sides: \[ 2500 H_1 = 2025 H_2 \] - Rearranging gives: \[ H_2 = \frac{2500 H_1}{2025} \] 5. **Substitute Initial Height:** - Let’s assume the initial height \( H_1 = 100 \) cm: \[ H_2 = \frac{2500 \times 100}{2025} = \frac{250000}{2025} \approx 123.46 \text{ cm} \] 6. **Calculate the Change in Height:** - The change in height \( \Delta H \) is: \[ \Delta H = H_2 - H_1 = 123.46 - 100 = 23.46 \text{ cm} \] 7. **Calculate the Percentage Increase in Height:** - The percentage increase in height is given by: \[ \text{Percentage Increase} = \left( \frac{\Delta H}{H_1} \right) \times 100 = \left( \frac{23.46}{100} \right) \times 100 = 23.46\% \] ### Final Answer: The percentage increase in height is approximately **23.46%**.
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