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PASSAGE-I: The area of a rhombus is (1)/...

PASSAGE-I: The area of a rhombus is `(1)/(2) (d_1 xx d_2)` and perimeter `= 2 sqrt( (d_1^2 + d_2^2 ) )`, where `d_1 and d_2` are the diagonals of the rhombus.
The area of the field in the form of rhombus if the length of each side be 14 cm and the altitude be 16 cm is

A

224 `cm^2`

B

210 `cm^2`

C

148 `cm^2`

D

228 `cm^2`

Text Solution

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The correct Answer is:
To find the area of the rhombus given the length of each side and the altitude, we can follow these steps: ### Step-by-Step Solution 1. **Understand the properties of a rhombus**: A rhombus is a type of parallelogram where all sides are equal in length. The area of a rhombus can also be calculated using the formula for the area of a parallelogram, which is given by: \[ \text{Area} = \text{Base} \times \text{Height} \] 2. **Identify the base and height**: In this case, the length of each side of the rhombus (which acts as the base) is given as 14 cm. The altitude (height) of the rhombus is given as 16 cm. 3. **Substitute the values into the area formula**: \[ \text{Area} = \text{Base} \times \text{Height} = 14 \, \text{cm} \times 16 \, \text{cm} \] 4. **Calculate the area**: \[ \text{Area} = 14 \times 16 = 224 \, \text{cm}^2 \] 5. **Conclusion**: The area of the rhombus is 224 cm². ### Final Answer The area of the rhombus is **224 cm²**. ---
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